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lang: interfaces: API changes for lambdas

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Co-authored-by: Samuel Gélineau <gelisam@gmail.com>
This commit is contained in:
James Shubin
2023-09-25 17:02:42 -04:00
parent 1eae5cf272
commit fcc76809e3
2 changed files with 6 additions and 5 deletions
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7
lang/interfaces/ast.go
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@@ -107,7 +107,7 @@ type Expr interface {
Ordering(map[string]Node) (*pgraph.Graph, map[Node]string, error) Ordering(map[string]Node) (*pgraph.Graph, map[Node]string, error)
// SetScope sets the scope here and propagates it downwards. // SetScope sets the scope here and propagates it downwards.
SetScope(*Scope) error SetScope(*Scope, map[string]Expr) error
// SetType sets the type definitively, and errors if it is incompatible. // SetType sets the type definitively, and errors if it is incompatible.
SetType(*types.Type) error SetType(*types.Type) error
@@ -122,8 +122,9 @@ type Expr interface {
Unify() ([]Invariant, error) Unify() ([]Invariant, error)
// Graph returns the reactive function graph expressed by this node. It // Graph returns the reactive function graph expressed by this node. It
// also returns the function for this node. // takes in the environment of any functions in scope. It also returns
Graph() (*pgraph.Graph, Func, error) // the function for this node.
Graph(env map[string]Func) (*pgraph.Graph, Func, error)
// SetValue stores the result of the last computation of this expression // SetValue stores the result of the last computation of this expression
// node. // node.

4
lang/interfaces/structs.go
View File

@@ -76,7 +76,7 @@ func (obj *ExprAny) Ordering(produces map[string]Node) (*pgraph.Graph, map[Node]
// SetScope does nothing for this struct, because it has no child nodes, and it // SetScope does nothing for this struct, because it has no child nodes, and it
// does not need to know about the parent scope. // does not need to know about the parent scope.
func (obj *ExprAny) SetScope(*Scope) error { return nil } func (obj *ExprAny) SetScope(*Scope, map[string]Expr) error { return nil }
// SetType is used to set the type of this expression once it is known. This // SetType is used to set the type of this expression once it is known. This
// usually happens during type unification, but it can also happen during // usually happens during type unification, but it can also happen during
@@ -145,7 +145,7 @@ func (obj *ExprAny) Func() (Func, error) {
// that fulfill the Stmt interface do not produces vertices, where as their // that fulfill the Stmt interface do not produces vertices, where as their
// children might. This returns a graph with a single vertex (itself) in it, and // children might. This returns a graph with a single vertex (itself) in it, and
// the edges from all of the child graphs to this. // the edges from all of the child graphs to this.
func (obj *ExprAny) Graph() (*pgraph.Graph, Func, error) { func (obj *ExprAny) Graph(env map[string]Func) (*pgraph.Graph, Func, error) {
graph, err := pgraph.NewGraph("any") graph, err := pgraph.NewGraph("any")
if err != nil { if err != nil {
return nil, nil, err return nil, nil, err